I need help solving this
...
![answer](/tpl/images/cats/otvet.png)
Answers: 3
Other questions on the subject: Mathematics
![image](/tpl/images/cats/mat.png)
![image](/tpl/images/cats/mat.png)
Mathematics, 21.06.2019 22:00, victordguerrero2535
Serena is making an experiment. for that, she needs 20 grams of a 52% solution of salt. she has two large bottles of salt water: one with 40% and the other with 70% of salt in them. how much of each must she use to make the solution she needs? i am in need of
Answers: 1
![image](/tpl/images/cats/mat.png)
![image](/tpl/images/cats/mat.png)
Mathematics, 22.06.2019 01:00, SpeechlessZzz9920
For every corresponding pair of cross sections, the area of the cross section of a sphere with radius r is equal to the area of the cross section of a cylinder with radius and height 2r minus the volume of two cones, each with a radius and height of r. a cross section of the sphere is and a cross section of the cylinder minus the cones, taken parallel to the base of cylinder, is the volume of the cylinder with radius r and height 2r is and the volume of each cone with radius r and height r is 1/3 pie r^3. so the volume of the cylinder minus the two cones is therefore, the volume of the cylinder is 4/3pie r^3 by cavalieri's principle. (fill in options are: r/2- r- 2r- an annulus- a circle -1/3pier^3- 2/3pier^3- 4/3pier^3- 5/3pier^3- 2pier^3- 4pier^3)
Answers: 3
Do you know the correct answer?
Questions in other subjects:
![Konu](/tpl/images/cats/mkx.png)
Arts, 04.10.2021 05:00
![Konu](/tpl/images/cats/mat.png)
Mathematics, 04.10.2021 05:00
![Konu](/tpl/images/cats/himiya.png)
![Konu](/tpl/images/cats/mat.png)
![Konu](/tpl/images/cats/mat.png)
![Konu](/tpl/images/cats/en.png)
![Konu](/tpl/images/cats/istoriya.png)
![Konu](/tpl/images/cats/himiya.png)
![Konu](/tpl/images/cats/ekonomika.png)
![Konu](/tpl/images/cats/biologiya.png)
Biology, 04.10.2021 05:00