Mathematics, 23.04.2020 15:08, suicune19

On a coordinate plane, a parabola opens down. It goes through (negative 2, negative 2), has a vertex at (1.5, 10), and goes through (5, negative 2).
Over which interval is the graph of f(x) = –x2 + 3x + 8 increasing?

(–∞, 1.5)
(–∞, 10.25)
(1.5, ∞)
(10.25, ∞)

Answers: 1

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On a coordinate plane, a parabola opens down. It goes through (negative 2, negative 2), has a vertex at (1.5, 10), and goes through (5, negative 2). Over which interval is the graph of f(x) = –x2 + 3x + 8 increasing? (–∞, 1.5) (–∞, 10.25) (1.5, ∞) (10.25, ∞)

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On a coordinate plane, a parabola opens down. It goes through (negative 2, negative 2), has a vertex at (1.5, 10), and goes through (5, negative 2).
Over which interval is the graph of f(x) = –x2 + 3x + 8 increasing?

(–∞, 1.5)
(–∞, 10.25)
(1.5, ∞)
(10.25, ∞)