One letter weighs 12 ounces. The mail carrier is allowed to carry 30 pounds. How many letters is he able to carry? 16 letters 32 letters 40 letters 480 letters

He is able to carry 40 letters

Step-by-step explanation: The total weight the mail carrier is allowed is 30 pounds, whereas each letter weighs 12 ounces.

What we need to do is simply find the rate of conversion between an ounce and a pound.

By conversion, 1 ounce equals 0.0625 pounds, that is;

1 ounce = 0.0625 pounds

Therefore 12 ounces would be 0.0625 times 12 which equals, 0.75 pounds. This means one letter weighs an equivalent of 0.75 pounds. If the mail carrier is allowed to carry a total of 30 pounds, then he can carry;

No of letters = Total weight allowed/weight of one letter

No of letters - 30/0.75

No of letters = 40

Hence the mail carrier is able to carry 40 letters.

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

answer:   the paragraph proof is mentioned below.

step-by-step explanation:

given: in a δxwy where

such that, ∠wzx ≅ ∠yzx and zw≅zy

we have to prove that: segment zx is a perpendicular bisector of segment wy.

prove: since, zw≅zy ⇒ ∠wzy is a supplementary angle.

then, ∠wzy= 180°

⇒∠wzx + ∠yzx = 180° ( because xz divides ∠wzy into two parts)

but, ∠wzx ≅ ∠yzx ( given)

⇒∠wzy+∠wzy=180° ( by substitution)

⇒2∠wzy=180°

⇒∠wzy=90°

⇒∠wzy=∠yzx =90°

therefore, xz⊥wy where wz=zy

⇒zx is a perpendicular bisector of wy.