Read the proof.
Given: AE 1 EC; BD IDC
Prove: AAEC ~ ABDC
Statement
Reason
1. AE 1 EC;BD1DC
1. given
2. ZAEC is a rt. 2; ZBDC is a 2. definition of
Irt. 2
perpendicular
3. ZAEC = ZBDC
3. all right angles are
congruent
14. ?
4. reflexive property
5. AAEC - ABDC
5. AA similarity theorem
What is the missing statement in step 4?
O ZACE = ZBGB
OZEAB = ZDBC
O ZEAC = EAC
O ZCBD = ZDBC

to find the perimeter of the rectangle this is the expression:

x-9+x-9+3x-4+3x-4=138

if we simplify it:

8x-26=138

remember, 138 is what it all adds up to

the length is 11.5cm

the width is 57.5cm

the area is 661.25cm^2

the answers might not be correct use at own risk

hence, the required result is

step-by-step explanation:

suppose we have two matrices a and b

we will assume the two matrices

we have to compute b-a which means subtracting corresponding elements of a from b.

-

7.9m and 4.3°

step-by-step explanation:

let east be +x and north be +y, x = distance * cos θ, y = distance * sin θ  

for 3.5 south, y = -3.5  

for 8.2, x = 8.2 * cos 30 and y = 8.2 * sin 30  

for 15 west, x = -15  

total x = 8.2 * cos 30 – 15 ≈ -7.9  

total y = -3.5 + 8.2 * sin 30 = 0.6  

magnitude = [(8.2 * cos 30 – 15)^2 + 0.6^2)]^0.5  

the magnitude is approximately 7.9 m  

tan θ = y/x = 0.6/-7.9  

the angle is approximately 4.3˚ north of west