Two plumbers charge different rates for service. The first plumber charges $100 for every service call plus $25 per hour of service. The second plumber charges $50 for every service call plus $50 per hour of service. After how many hours do the plumbers charge the same amount

After two hours the two plumbers will charge the same amount

Set up your equations

Plumber 1:

y = 25x + 100

Plumber 2:

y = 50x + 50

Set the two equal to each other and solve

25x + 100 = 50x + 50

         -50              -50

25x + 50 = 50x

-25x           -25x

           50 = 25x

     50/25 = 25x/25  <- Divide both sides by 25

              x = 2

After two hours the two plumbers will charge the same amount

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet