Mathematics, 23.04.2020 01:05, aedmund1225
A quantity with an initial value of 830 grows exponentially at a rate such that the quantity doubles every 2 weeks. What is the value of the quantity after 21 day, to the nearest hundredth?
Answers: 1
= initial number of quantity
![\Rightarrow (1+r)=\sqrt[14]{2}](/tpl/images/0620/0575/b902f.png)
![\Rightarrow r=\sqrt[14]{2}-1](/tpl/images/0620/0575/9fa65.png)
![A=830( 1+\sqrt[14]{2}-1)^{21}](/tpl/images/0620/0575/bd110.png)
![\Rightarrow A=830(\sqrt[14]2)^{21}](/tpl/images/0620/0575/544c7.png)
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A quantity with an initial value of 830 grows exponentially at a rate such that the quantity doubles...
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