Suppose ADB pays an interest of 2%, Barclays pays an interest of
4% and GCB pays an interest of 5% per annum and an amount of ¢350 more was invested in
Barclays than the amount invested in ADB and GCB combined. Also, the amount invested in
Barclays is 2 times the amount invested in GCB.

Correction

Amounts invested in each bank:

GCB=$1,713,33    

Barclays=$3,426.66

ADB=$1,363.33

Step-by-step explanation:

-Given that ADB pays 2% pa, GCB pays 4% and Barclays pays 5%

-From the information provided, the amount invested in each of the 3 banks can be expressed as:

-Let X be the Amount invested in GCB:

-Since the total interest earned on all 3 accounts after 1 year is $250, we can equate and solve for X as below:

Hence, the amounts invested in each bank is GCB=$1,713,33    ,   Barclays=$3,426.66 and ADB=$1,363.33

answer: group b.

step-by-step explanation:

cross multiplying, we get :

⇒ (3) × (5) = (9) × (x)

⇒ 15 = 9x