How much water should we add to 5 gallons of 18% acid solution to dilute it to a concentration of 10%?
We should add
gallons of water to dilute the concetration.

4 gallons of water is needed to dilute to a concentration of 10%.

Step-by-step explanation:

It is given that,

The 5 gallons of water contains 18% of acid solution.

Now, we are asked to find the gallons of water needed to dilute it to a concentration of 10% acid solution.

We obtain the equation by stating that the amount of acid 10% in the water must dilute up to 18%.

For this, x amount of water should be added.

Therefore, the equation is framed as,

⇒ 0.1 (x+5) = 5 (0.18)

⇒ 0.1x + 0.5 = 0.9

⇒ 0.1x = 0.9 - 0.5

⇒ x = 0.4 / 0.1

⇒ x = 4

∴ 4 gallons of water is needed to dilute to a concentration of 10%.

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!