What is the equation of the circle with center (1,1) that passes through the point (-3,4)?

(x - 1)2 + (y - 1)² = 5²

Step-by-step explanation:

Adapt the standard equation of a circle with center at (h, k) and radius r:

(x - 1)^2 + (y - 1)^2 = r^2

Here one point on the circle is (-3, 4), and so the radius is √[(-3)² + 4² ] = 5

Thus, the desired equation is:

(x - 1)^2 + (y - 1)^2 = 5^2      or     (x - 1)2 + (y - 1)² = 5²

answer: it is 1: 47 pm

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !