The score of golfers for a particular course follows a normal distribution that has a mean of 73 and a standard deviation of 3. Suppose a golfer played the course today. Find the probability that her score is at least 74.

0.3694

Step-by-step explanation:

In this question, we are asked to calculate the probability that a golfer scored at least 74 if she played on a particular day.

Given that ,

mean = µ = 73

standard deviation = σ = 3

P(x > 74) = 1 - P(x<74 )

= 1 - P[(x -µ) / σ < (74 -73) /3 ]

= 1 - P(z <0.3333 )

Using z table

= 1 - 0.6305

= 0.3694

probability= 0.3694

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

10

step-by-step explanation: