The area of an isosceles trapezoid is 45 cm2 and its height is 5 cm. Find the perimeter if one of the legs is 2 3 of the sum of the bases.

Step-by-step explanation:

The formula for determining the area of a trapezoid is expressed as

Area = 1/2(a + b)h

Where

a and b are the length of the 2 parallel sides or bases of the trapezoid. Since it is an isosceles trapezoid, then the length of the 2 legs are equal.

h represents the height of the trapezoid.

From the information given,

Area = 45cm²

h = 5 cm

45 = 1/2(a + b)5

2 × 45 = 5(a + b)

90 = 5(a + b)

a + b = 90/5 = 18

if one of the legs is 2/3 of the sum of the bases, it means that the height of each leg is

2/3 × 18 = 12 cm

The length of both legs is

12 × 2 = 24 cm

The perimeter of the trapezoid is

Sum of bases + sum of legs

Therefore,

Perimeter = 18 + 24 = 42 cm

f(x) has value 150 at x= 0

and 0 at x= 3

so d(f(x))/dt = slope = -150/3 = -50

hello,

b) 62.47% of the students are between 14 and 18 years old.

step-by-step explanation:

mean = 15 and standard deviation = 2

student between 14 to 18

formula used z-score

for age 14 , z score

using z-table , p(z> -0.5)=0.3085

for age 18 , z score

using z-table , p(z< 1.5)=0.9332

p(-0.5< z< 1.5)=0.9332-0.3085 = 0.6247

thus, 62.47% of the students are between 14 and 18 years old.

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