What is the cost of a new trampoline cover that needs to cover a trampoline with a diameter of 8 feet if the material cost 6.75 per square foot?

The cost of the trampoline cover would be $339.12

Step-by-step explanation: The radius of the trampoline is 4 feet (Diameter divided by 2 equals radius).

The trampoline cover will effectively cover the entire area of the trampoline and the area is given as

Area of circle = πr²

Area of circle = 3.14 x 4²

Area of circle = 3.14 x 16

Area of circle = 50.24 square foot

However the material costs $6.75 per square foot, which means the total cost of the trampoline cover would be derived as

Total area x cost per square foot = cost of trampoline cover

50.24 x 6.75 = Cost of trampoline cover

$339.12 = Cost of trampoline cover

 The cost of the new trampoline cover is $339.29

Step-by-step explanation:

Hi, we have to calculate the area of the trampoline cover.

Since it has a circle form with a 8 ft diameter.

Area of a circle = π r^2

Since the radius (r) is equal to the diameter (d) divided by 2

R = d/2 = 8/2 =4

Replacing in the formula:

A = π 4^2 = 50.26 square ft

Since the material cost 6.75 per square foot

Cost = 6.75 x 50.26 = $339.29

example answer: "to determine if a sum is reasonable you can round each number to the nearest whole and compare the estimated sum to the actual sum."

hope this you and anyone else who needs the answer : ^)