C) The following table shows the values, in thousands of dollars, of 40 randomly selected houses in the city.

34 38 95 110 137 140 155 155 169 207
209 217 274 314 314 323 343 347 349 363
369 373 388 389 397 416 448 450 483 487
488 516 571 595 600 738 762 769 863 1,084
(i) Calculate the sample midrange for the data.

The midrange is 559?

(ii) Explain why the sample midrange might be preferred to the sample mean as an estimator of the population mean.

Is the midrange preferred because the data is skewed? I need major help please! Brainliest for who answers correctly! No hints just answers!

i need the table so i can see

step-by-step explanation:

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;

on monday rodney ate 1/4th of the sandwich = 3/12

on tuesday he ate 1/3rd of the sandwich = 4/12

therefore in total he has eaten = 3/12 + 4/12 = 7/12

thus we can say that he has eaten 7/12 of the sandwich on monday and tuesday alltogether.

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