Find the vertical asymptotes of the following function:

y=x+2

x^2 +2x−8

Select the appropriate response:

A) horizontal asymptotes x = −4, 5

B) horizontal asymptotes x = −4, 4

C) vertical asymptotes x = −8, 4

D) vertical asymptotes x = −4, 2

Help please! 50 points!

D) vertical asymptotes x = −4, 2

Step-by-step explanation:

x² + 2x - 8 = 0

x² + 4x - 2x - 8 = 0

x(x + 4) - 2(x + 4) = 0

(x + 4)(x - 2) = 0

x = 2, -4

to plot points   for x just start at the origin (middle) and go to the left however many times it say(if the number is a positive) if the number is a negative then go right however many times it says if it is 0 go nowhere

now keep you pencil there and go up however many times it says on y(if it is positive) if it is negative then go down however many times it says. if it says 0 go nowhere.

you have just plotted a point! now when you finish plotting all of them connect them with a ruler

plot each point as (-3, 7), (0,4), (3,1), (8,-4)   in the parenthesis on the left of the comma is x and the right is y.

step-by-step explanation:

let

we know that

the y-intercept is the y-coordinate of the point when the value of x is equal to zero

so

the y-coordinate of the point a is the y-intercept

the answer part a) is

the value of y-intercept is

part b) find the slope m

we know that

the value of the slope is equal to

substitute the values

therefore

the answer part b) is

the value of the slope is equal to

the general answer is

the slope is

the value of y-intercept is