An eight-sided die, which may or may not be a fair die, has four colors on it; you have been tossing the die for an hour and have recorded the color rolled for each toss. What is the probability you will roll an orange on your next toss of the die? Express your answer as a simplified fraction or a decimal rounded to four decimal places.

Probability of an Orange on the next toss

= (23/60) = 0.3833

Step-by-step explanation:

Orange: 46

Brown: 23

Green: 32

Yellow: 19

Probability of an Orange on the next toss

= n(orange colours obtained in the tosses) ÷ n(number of tosses)

n(orange colours in the tosses) = 46

Total number of tosses = 46 + 23 + 32 + 19

= 120.

Probability of an Orange on the next toss

= (46/120) = (23/60) = 0.3833

Hope this Helps

answer:

it is general formula that is used to write value to its excet position

a11 a12 a13

a21 a22 a23

it is the example of order 2 by 3 matrix in this

a11 means value occur in 1 st row 1st column

a12 means value occurs in 1st row 2nd column

a13 means value occur in 1st row and 3rd column

a21 means value occurs in 2nd row and 1st column

a22 means value occurs in 2nd row and in 2nd column

a23 means value occurs in 2nd row and in 3rd column