Suppose that an individual lives for two periods. The individual (as per usual) has 16 hours of time to devote to leisure or work in each period. The individual gets a wage of $20 in period 1 and a wage of $25 in period 2. The interest rate in this economy is 10%. The individual also receives a non-labour income of $10 in each period. The utility of the individual depends on whether she is injured or not (as she really dislikes going to work if she is hurting). Her utility in period t if she is unijured is given by u(a, h) = {In(c) + In() while it is given by by u(a, lt) = n(q) + ln(l) if she is injured. The individual also faces a borrowing constraint of $10. a. (15 points) Find the hours worked each period if the individual is uninjured in period 1 and is able to predict that she will be injured in period 2 (e. g., injury is arthritis that she knows will get worse in period 2). b. (5 points) From part (a) (i. e., she can predict her injury), explain in two or three sentences whether the individual will work more or less in period 2 if there is a borrowing constraint of $10. c. (20 points) Suppose that instead that the individual was uninjured in period 1 and was expected to remain uninjured in period 2. To her surprise, though, she gets injured in period 2 (e. g., injury was received by a brutal slash while playing hockey). How many hours does the individual work in period 2 now?

Cone w has a radius of 8 cm and a height of 5 cm. square pyramid x has the same base area and height as cone w. paul and manuel disagree on how the volumes of cone w and square pyramid x are related. examine their arguments. which statement explains whose argument is correct and why? paul manuel the volume of square pyramid x is equal to the volume of cone w. this can be proven by finding the base area and volume of cone w, along with the volume of square pyramid x. the base area of cone w is π(r2) = π(82) = 200.96 cm2. the volume of cone w is one third(area of base)(h) = one third third(200.96)(5) = 334.93 cm3. the volume of square pyramid x is one third(area of base)(h) = one third(200.96)(5) = 334.93 cm3. the volume of square pyramid x is three times the volume of cone w. this can be proven by finding the base area and volume of cone w, along with the volume of square pyramid x. the base area of cone w is π(r2) = π(82) = 200.96 cm2. the volume of cone w is one third(area of base)(h) = one third(200.96)(5) = 334.93 cm3. the volume of square pyramid x is (area of base)(h) = (200.96)(5) = 1,004.8 cm3. paul's argument is correct; manuel used the incorrect formula to find the volume of square pyramid x. paul's argument is correct; manuel used the incorrect base area to find the volume of square pyramid x. manuel's argument is correct; paul used the incorrect formula to find the volume of square pyramid x. manuel's argument is correct; paul used the incorrect base area to find the volume of square pyramid x.