Solve for x
3 x − 8 ≤ 23 AND − 4 x + 26 ≥ 6
Please help thank you!!

To solve for x, you need to isolate/get the variable "x" by itself in the inequality:

3x - 8 ≤ 23       Add 8 on both sides

3x - 8 + 8 ≤ 23 + 8

3x ≤ 31         Divide 3 on both sides to get "x" by itself

    (x is any number less than or equal to 31/3)

-4x + 26 ≥ 6          Subtract 26 on both sides

-4x ≥ -20      Divide -4 on both sides [When you multiply/divide by a negative number to both sides of an inequality, you flip the sign </>]

  (two negative signs cancel each other out and become positive)

x ≤ 5     (x is any number less than or equal to 5)

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

                      )

triangle abd and cba are similar,

                            (2)

triangle cad and cba are similar,

                      )

using (1), (2) and (3), we get

hence proved.

therefore option 2 is correct.

6. 104

7. 52/37

8. 2704

9. 140608

10. -52

11. |52|=52

12. 1/52

13. 156

14. 26

15. 40

16. 37

17. -364

18. 53 1/3

19. 50.96

20. 43 2/3

21. 78

22. 50.75

23. 47.63

24. 163.28

25. 10400

26. 338

27. 208

28. 2704 square inches

29. 312 square meters

30. don't know what its asking, tell me so i can tell you

31. 8490.56

32. 52 degrees would be an acute angle

33. 128 degrees

34. 20.8

35. 39

36. 208