Mathematics
Mathematics, 21.04.2020 21:30, makenziehook8

The maximum value of f (x )equals fraction numerator 2 over denominator 1 minus e to the power of negative 2 x end exponent end fractionover the interval left square bracket 2 comma space infinity )is A. fraction numerator 4 over denominator 1 minus e to the power of negative 6 end exponent end fraction B. fraction numerator 1 over denominator 1 minus e to the power of negative 3 end exponent end fraction C. fraction numerator 3 over denominator 1 minus e to the power of negative 5 end exponent end fraction D. fraction numerator 2 over denominator 1 minus e to the power of negative 4 end exponent end fraction

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