A researcher conducts a related-sample study to evaluate two treatments with n = 16 participants and obtains a t statistic of t = 1.94. The treatment 2 is expected to have a greater sample mean than the treatment 1. What is the correct decision for a hypothesis test using α = .05?

Not enough statistical evidence to prove that treatment 2 sample mean u2 is less than treatment 1 sample mean u1. So the claim may be supported.

Step-by-step explanation:

Solution:-

- The sample size of two treatments, n = 16

- The mean of sample treatment 1, u1

- The mean of sample treatment 2 , u2

- The significance level, α = .05

- State the hypothesis:

                      Null hypothesis : u2 - u1 > 0

                      Alternate hypothesis : u2 - u1 ≤ 0

- The rejection region of the T- critical for lower tailed test.

                      significance level, α = .05

                      degree of freedom v = n - 1 = 16 - 1 = 15

                      T-critical =  - 1.75

- The T-test value is compared with T-critical:

                      T-test = 1.94

                      T- critical = -1.75

                      T-test > T-critical  .. ( Null not rejected )

- Not enough statistical evidence to prove that treatment 2 sample mean u2 is less than treatment 1 sample mean u1. So the claim maybe supported.

answer: given that the roller coaster can accommodate 1600 riders per hour, thus the roller coaster can accomodate 1600 / 60 = 26.67 riders per minute.

given that there are 345 people in the line, the number of minutes it will take for the 345 persons to get into the roller coaster is given by 345 / 26.67 = 12.94 minutes.

therefore, it will take you 12.94 minutes to get to the front of the line.

step-by-step explanation:

the answer is 489

step-by-step explanation: