If we take samples from normal populations and construct two confidence intervals (CI) for which the only difference is that one of them was at the 80% confidence level and the other was at the 90% level, which of the following statements is true? Group of answer choices The margin of error is larger in the 90% CI than in the 80% CI. The margin of error is the same in the 90% CI as it is in the 80% CI. The margin of error is smaller in the 90% CI than in the 80% CI. There is not enough information to determine which of the above statements is true.

The margin of error is larger in the 90% CI than in the 80% CI.

Step-by-step explanation:

Confidence interval is written as

Sample mean ± margin of error

Margin of error = z × population standard deviation/number of samples

The z score for a 90% confidence level(1.645) is higher than the z score for a 80% confidence level(1.282)

If all other parameters(sample size and population standard deviation) remain the same, then the true statement is

The margin of error is larger in the 90% CI than in the 80% CI.

a

step-by-step explanation:

a

0.16 or 16%

step-by-step explanation:

lets take a coin for example.

if you toss it twice, it has a 1/4 chance of landing on heads both times because 1/2 * 1/2 is 1/4.

with the cards, the chance of picking dog is 0.4. having two people pick one is like picking a card twice in a row. so 0.4 * 0.4 is 0.16, or 16%