A ship leaves port at 1:00 pm and travels Upper N 70 degrees Upper WN70°W at the rate of 10 mph. Another ship leaves the same port at 1:30 pm and travels Upper S 10 degrees Upper ES10°E at the rate of 8 mph. How far apart in miles are the ships at 3:00 pm ?

30.4 miles

Step-by-step explanations:

Please refer to the attached image for explanations

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐