Which of the following lines would be perpendicular to a line whose equation is y=1/2x-7 and pass through the point (-10,7)?

The answer to your question is     y = -2x - 13

Step-by-step explanation:

Data

Original line    y = 1/2x - 7

Point = (-10, 7)

New line = ?

Process

1.- Find the slope of the original line

    The slope is the coefficient of the x

                     y = 1/2x - 7

    slope = 1/2

2.- Find the slope of the new line

The new line is perpendicular to the original line

    slope = -2

3.- Find the equation of the new line

          y - y1 = m(x - x1)

          y - 7 = -2(x + 10)

-Simplification

          y - 7 = -2x - 20

          y = -2x - 20 + 7

          y = -2x - 13

the transverse axis of a hyperbola is the line that contains the two vertices and the two focuses.

in this example (hyperbola of equation x^2/2 - y^2/4 = 1), the transverse axis is the  x-axis  . 

step-by-step explanation: