A metal rod is being carried down a corridor which is 7 feet wide. At the end of the corridor there is a right-angle turn (to the right) into a wider corridor whichis 8 feet wide. What is the length of the longest metal rod which can be carried horizontallyaround the right-angle turn

Length of the longest metal rod which can be carried horizontally around the right-angle turn is 21.21ft

Step-by-step explanation:

Length of the longest metal rod which can be carried horizontally around the right-angle turn, can be determined at the point at where the distance between one end of rod and the 7feet corridor is same as the distance between other end of the rod and the 8feet corridor. How do I mean.

The length of longest metal rod will be determined when distance between the one end of rod and the 7feet corridor and the distance between other end of the rod and the 8feet corridor are both 15ft (7ft + 8ft).

See attachment for illustration.

Therefore using Pythagoras theorem we can find the length of longest metal rod that can be carried horizontally around the right angle turn

See illustration in attachment

i.e

Hyp² = opp²+adj²

Hyp = √(15²+15²)

Hyp = √450

Hyp = 21.21ft

3 is greater then both of those numbers

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation: