The drama club is selling tickets to their play to raise money for the show's expenses. Each student ticket sells for $8 and each adult ticket sells for $12. There was a total of $960 in revenue from the sale of 100 total tickets. Graphically solve a system of equations in order to determine the number of student tickets sold, x, x, and the number of adult tickets sold, y.

Step-by-step explanation:

The drama club is selling tickets to their play to raise money for the show's expenses.

Let the student ticket be represented as x and adult ticket as y

Cost of student ticket,x = $8

Cost of adult ticket,y = $12

The total number of tickets, x + y = 100 ... (1)

There was a total of $960 in revenue from the sale of 100 total tickets.

8x + 12y = 960 ...(2)

Multiplying eq(1) by 8, we get

8x + 8y = 800 ...(3)

Subtract eq (3) from (2), we get

4y = 160

y = 40, sub in eq (1)

x = 60

The no of student ticket, x = 60

The no of adult ticket, y =40

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2