In a class of 7 students, there are 5 students who forget their lunch. If the teacher chooses 2 students, what will the probability that neither of them forget their lunch?

4711

Step-by-step explanation:

Answer by rothauserc(4711)   (Show Source):  

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the probability that the first student picked has a lunch is 6/9 or 2/3

the probability that the second student picked has a lunch is 5/8

$9.89

step-by-step explanation:

9.90 = p x .06 x .25 (3/12 changed to a decimal)

9.90 = p x 0.015

9.90 - 0.015 = p

9.89 = p

7.25

step-by-step explanation:

we know that 7 equals to 7.0. we also know that 1/4=0.25. so we can add the two together and we get 7.25