What is the probability of a die landing on an even number on the first toss, and then an odd number on the second toss?
Dice- 6 sides

Please help

1/4 chance

Step-by-step explanation:

Number of even numbers on a die-3

Number of odd numbers on a die-3

a die has 6 sides,

therefore

1/2 of the numbers on a die are even and 1/2 are odd

so a 3/6 chance (1/2 chance (simplify)) of landing on an even number on the first roll

And  a 3/6 chance (1/2 chance (simplify)) of landing on an odd number on the second roll

Multiply the two together and a 9/36 chance of this event or simplified to a 1/4 chance of this event

m∠5 + m∠3 = m∠1   is true.

m∠5 + m∠6 = 180 is true

m∠2 +m∠3 = m∠6   is true

m∠2 +m∠3 +m∠5 = 180   is true

1.) 21

2.) 0.453

3.) 1.5

4.) 48

5.) $ 22

step-by-step explanation: