What is the slope of the original line?
Use the slope of the given line to construct a parallel line
through point P. Click or tap the graph to plot another point on
the parallel line.
What is the slope of the original line?
-1/2
-1
1
1/2
What is the equation of the line that is parallel to the
given line and passes through the given point?
y-3=-1(x-3)
Y-3 = 1(x-3)
y + 3 =-1(x + 3)
y + 3 = 1(x +3)

for this case we have by definition, if two lines are perpendicular, then the product of their slopes is -1.

then, given the following line:

so,

we are looking for m_ {2}:

then, the line is given by:

we find "b" replacing the given point:

finally, the equation is:

option c

vhhhbnbb. ddben jenner v

is the anwser b. (-13)?

one way is to plot 2 points and connect them which is what the answer choices seem to be doing

it seems to be using the y intercept and the slope

y=mx+b, m=slope, b=y-intercept (where the line hits the y axis)

slope=rise/run

y-intercept is where the line croses the y axis which is the y value where x=0

you seem to have given the wrong slope (you didn't put a number in front of te x, it should be 2/3 or 3/2 looking at the answer options)

y=? x-1

m=? because of your fault

b=-1

so it has a slope of ? and y intercept of -1, meaning it pases through (0,-1)

so draw point (0,-1) (so answer is one of the first 2 option)

if slope is 2/3, then go up 2 and right 3 then draw line through those 2 points

if slope is 3/2, then go up 3 and right 2 then draw line through those 2 points