What are the solutions to log6(x squared + 8) = 1 + log6(x)
x = -2 and x = --4
x =-1 and x = 8
x = 1 and x =-8
x = 2 and x = 4

x = 2 and x = 4

Step-by-step explanation:

log6(x squared + 8) = 1 + log6(x)

log6(x squared + 8) = log6(6) + log6(x)

log6(x² + 8) = log6(6x)

x² + 8 = 6x

x² - 6x + 8 = 0

x² - 4x - 2x + 8 = 0

x(x - 4) - 2(x - 4) = 0

(x - 4)(x - 2) = 0

x = 2, 4

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

answer: y = -2.5x - 15

              (-6,0)

step-by-step explanation: