Write the equation of the line with a slope of -5 and a y-intercept of (0,3).

write the equation of the line with a slope of -1/3 and passing through the point (6, -4).

write the equation of the line passing through the points (0, -4) and (-2, 2).

write the equation of the line passing through the points (-6,1) and (-4,2).

write the equation of the line with an undefined slope, passing through the point (2, 5).

Equation of the line with slope -5 and y intercept (0,3)
y = mx + b
y = -5x + 3
equation of line with slope -1/3 and passing through the point (6, -4)
y-y1 = m(x-x1)
y-(-4) = (-1/3)(x - 6)
y+4 =(-1/3)(x-6)
3(y+4) = -1(x-6)
3y + 12 = -x + 6
x + 3y + 12 - 6 = 0
x + 3y + 6 = 0
equation of line passing through the points (0, -4) and (-2, 2)
(y - y1)/(y2 - y1) = (x-x1)/(x2-x1)
(y + 4)/(2 + 4) = (x - 0)/(-2-0)
(y+4)/6 = x/-2
-2(y+4) = 6x
-2y - 8 = 6x
6x + 2y + 8 = 0
equation of line passing through the points (-6, 1) and (-4, 2)
(y - y1)/(y2-y1) = (x-x1)/(x2-x1)
(y-1)/(2-1) = (x+6)/(-4+6)
(y-1)/1 = (x+6)/2
2(y-1) = (x+6)
2y - 2 = x + 6
x - 2y + 6 + 2
x - 2y + 8 = 0
equation of line undefined slope passing through the point (2, 5)
y - y1 = m(x-x1)
y - y1 = tanФ(x-x1)
y - 5 = (∞)(x-2)
y - 5 = (1/0)(x-2)
0(y-5) = (x-2)
0 = x - 2
x - 2 = 0

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12