There are three consecutive integers. The product of the first and the last is 35 more than 5 times the second number. Find these integers.

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Please show all work (don't show 5+4 = 9 but you get the idea)

8,9,10

Step-by-step explanation:

Let x-1, x and x+1 be the consecutive integers

(x-1)(x+1) = 5x + 35

x² - 1 - 5x - 35 = 0

x² - 5x - 36 = 0

x² - 9x + 4x - 36= 0

x(x - 9) + 4(x - 9) = 0

(x - 9)(x + 4) = 0

x = 9, -4

Step-by-step explanation:

hello :

let this three consecutive integers : x  , x+1  , x+2

x(x+2)=35+5(x+1)

x²+2x=35+5x+5

x²-3x-40=0

(x-8)(x+5)=0   x+5 ≠ 0 because : x integer

x-8=0   so : x=8

three consecutive integers are : 8 and 9 and 10

answer: ur v dumb

step-by-step explanation:

square root of 36/6 = 2.449489743

square root of 16/6 = 1.632993162

square root of 6 = 2.449489743

the answer is square root of 16/6 because the square root of 36/6 is the same answer as square root of 6 = 2.449489743