What is the vertex form of the equation

y= -x^2+10x-30

The answer to your question is Vertex = (5 , -5)

Step-by-step explanation:

Data

Equation                y = - x² + 10x - 30

Process

1.- Add 30 units in both sides

                             y + 30 = -x² + 10x - 30 + 30

2.- Simplify

                             y + 30 = -x² + 10x

3.- Factor -1 in the right side

                             y + 30 = -(x² - 10x      )

4.- Complete the perfect square trinomial

                             y + 30 - 5²= -(x² - 10x + 5²)

5.- Simplify

                             y + 30 - 25 = -(x² - 10x + 25)

                             y + 5 = -(x - 5)²

6.- Find the vertex

                            Vertex = (5 , -5)

here you hope this .

step-by-step explanation:

hypotenuse = √(15² + 8²)

=  √(225 +64)

=  √(289) = 17

sin(x) = cos(y) = 8/17

they are identical so long as you are doing the sine of one angle and the cosine of the only other angle that isn't the right angle.