(Photo attached) Trig question. Thanks in advance! :)

  a) cos(α+β) ≈ 0.8784

  b) sin(β -α) ≈ -0.2724

Step-by-step explanation:

There are a couple of ways to go at these. One is to use the sum and difference formulas for the cosine and sine functions. To do that, you need to find the sine for the angle whose cosine is given, and vice versa.

Another approach is to use the inverse trig functions to find the angles α and β, then combine those angles and find find the desired function of the combination.

For the first problem, we'll do it the first way:

  sin(α) = √(1 -cos²(α)) = √(1 -.926²) = √0.142524 ≈ 0.377524

  cos(β) = √(1 -sin²(β)) = √(1 -.111²) ≈ 0.993820

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a) cos(α+β) = cos(α)cos(β) -sin(α)sin(β)

  = 0.926×0.993820 -0.377524×0.111

  cos(α+β) ≈ 0.8784

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b) sin(β -α) = sin(arcsin(0.111) -arccos(0.926)) ≈ sin(6.3730° -22.1804°)

  = sin(-15.8074°)

  sin(β -α) ≈ -0.2724

step-by-step explanation:

sry but any answer choices