The population of a small town is decreasing at a rate of 7% per year. If the town's population is 13,250 now, what will be the approximate population in 10 years?

The approximate population of the small town after 10 years is 6,413

Step-by-step explanation:

Here we note that the general growth formula is given by;

For decreasing rate, we have;

Where:

A = Population after growth

P = Initial population = 13250

r = The annual reduction rate in decimals = 7 % = 7/100 = 0.07

t = Number of years of decrease= 10 years

Since the population is decreasing, then by plugging in our values into the above equation for decreasing rate, we have

= 6.412.766 ≈ 6,413

The approximate population of the small town after 10 years = 6,413

y=mx+b

step-by-step explanation:

m is slope, b is y-intercept

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )