The point(-6 7) on the circle with radius 5 and center (2 -9)

(-6, 7) is NOT on the given circle

Step-by-step explanation:

Write out the standard equation of a circle with center at (h, k) and radius r:

(x - h)^2 + (y - k)^2 = r^2, where (h, k) is the center and r is the radius.

Substituting 2 for h and -9 for k, and 5 for r, we get

(x - 2)^2 + (y + 9)^2 =5^2

Now determine whether or not the point (-6, 7) is on this circle:

Substituting -6 for x and 7 for y, we get:

(-6 - 2)^2 + (7 + 9)^2 =5^2    Is this true or false?

64 + 256 = 225?  NO.  Thus, (-6, 7) is NOT on the given circle.

step-by-step explanation:

you divide the denominator by the numerator on both sides and if the quotients are equal then the fractions are equivalent

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step-by-step explanation: