Please Help! <3 What is the center and the radius of a circle with the following equation.

So the center is (0,-4) and the radius is 6

Step-by-step explanation:

We can write the equation of a circle as

(x-h)^2 + (y-k) ^2 = r^2  where (h,k) is the center and r is the radius

We have

(x)^2 + (y+4) ^2 = 36

(x-0)^2 + (y- -4) ^2 = 6^2

So the center is (0,-4) and the radius is 6

Centre: (0,-4)

Radius: 6

Step-by-step explanation:

(x - h)² + (y - k)² = r²

(x - 0)² + (y - (-4))² = 6²

Centre: (0,-4)

Radius: 6

- 2 + 10x³ - 21x² + 19x - 4

step-by-step explanation:

each term in the second factor is multiplied by each term in the first factor

x²(- 2x² + 4x - 1) - 3x(- 2x² + 4x - 1) + 4(- 2x² + 4x - 1) ← distribute

= - 2 + 4x³ - x² + 6x³ - 12x² + 3x -8x² + 16x - 4

collect like terms

= - 2 + 10x³ - 21x² + 19x - 4 ← in standard form