Given the following problem, identify the vertex and the axis of symmetry.

A.
vertex is (–2, –2); axis of symmetry is x = 2
B.
vertex is (–2, 2); axis of symmetry is x = –2
C.
vertex is (2, –2); axis of symmetry is x = –2
D.
vertex is (–2, –2); axis of symmetry is x = –2

D.

vertex is (–2, –2); axis of symmetry is x = –2

Step-by-step explanation:

Vertex: (h,k) = (-2,-2)

Line of symmetry: x = h

So, x = -2

3< x< 5

step-by-step explanation:

|x - 4| < 1

there are two solutions, one positive and one negative.   remember to flip the inequality when taking the negative solution

x-4 < 1       x-4 > -1

add 4 to each side

x-4+4 < 1+4       x-4+4 > -1+4

x< 5                 x> 3

3< x< 5

y = 3x+4

step-by-step explanation:

to find the slope

slope = (y2-y1)/ (x2-x1)

    = (-8-4)/ (-4-0)

    = -12/-4

  = 3

using the slope intercept form of a line

y= mx+b

we know the slope is 3

we know the y intercept is 4 ( the point where it crosses the y axis or x=0)

y = 3x+4