Determine the equations of the vertical and horizontal asymptotes, if any, for g(x)= x-2/x2+4x+3

A. x= -1, x=3
B. x=-1, x= -3, y=0
C. x= -1, x=-3, y=0
D. x= -1, x= -3

the clb she uses is a driver, so its a 2/5 chance she hits a 180-189 yard shot

step-by-step explanation:

place r′ so that qr′ is parallel to the tangent.

now we get that ∠r′py=∠pr′q, where y is on the tangent, on the opposite side of p from x.

also, because of the symmetry, ∠r′py=∠qpx.

finally, note that no matter where we place r, as long as it's on the correct arc, we have ∠prq=∠pr′q.

stringing all these equalities together, we end up with ∠prq=∠qpx.

this picture will show how its going to look like.

hope this by jack monhen

1,2,4,5,10,11,20,22,44,55,110,220