If r(x) = 3x – 1 and s(x) = 2x + 1, which expression is equivalent to (StartFraction r Over s EndFraction) (6)?
StartFraction 3 (6) minus 1 Over 2 (6) + 1 EndFraction
StartFraction (6) Over 2 (6) + 1 EndFraction
StartFraction 36 minus 1 Over 26 + 1 EndFraction
StartFraction (6) minus 1 Over (6) + 1 EndFraction

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)

step-by-step explanation:

1332.

this is because to get from 333 to 999 you multiply by 3, and you should do the same to the number of hours.

therefore you would do 444*3=1332

it will take 9 minutes