(1 point) Take the Laplace transform of the following initial value problem and solve for Y(s)=L{y(t)}: y′′−5y′−14y=S(t)y(0)=0,y′(0)=0 where S is a periodic function defined by S(t)={1,0,0≤t<11≤t<2, and S(t+2)=S(t) for all t≥0. Hint: : Use the formula for the Laplace transform of a periodic function. Y(s)= (1-e^(-s))/(s(1-e^(-2s))) equation editorEquation Editor

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

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step-by-step explanation:

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