Mathematics, 16.04.2020 23:30, shymitch32
Find the arc length for the curve y = 5 x 2 β 1 40 ln x taking P 0 ( 1 , 5 ) as the starting point. If f ( x ) = 5 x 2 β 1 40 ln x , then f ' ( x ) = 1 + [ f ' ( x ) ] 2 = 1 + ( ) 2 = 1 + 100 x 2 β 0.5 + = 100 x 2 + 0.5 + ( ) 2 β 1 + [ f ' ( x ) ] 2 = . Thus the arc length is given by s ( x ) = β« x 1 β 1 + [ f ' ( t ) ] 2 d t = β« x 1 ( ) d t = [ ] x 1 = . For instance, the arc length along the curve from ( 1 , 5 ) to ( 5 , ) is s ( 5 ) = + 1 40 ln 5 β 5 = + ln 5 40 β (rounded to four decimal places).
Answers: 1
Mathematics, 21.06.2019 20:10, sksksksksk1
Heather is writing a quadratic function that represents a parabola that touches but does not cross the x-axis at x = -6. which function could heather be writing? fx) = x2 + 36x + 12 = x2 - 36x - 12 f(x) = -x + 12x + 36 f(x) = -x? - 12x - 36
Answers: 1
Find the arc length for the curve y = 5 x 2 β 1 40 ln x taking P 0 ( 1 , 5 ) as the starting point....
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