Given that A=(9,9,2), B=(1,3,5) and C=(5,6,4), find the vector equation of the line through A and B.
a r={8,6.–3}+t(9,2)
C. r= (9,9,2) - t(-8, 6,- 3)
b. r=(9,9,2) +t(-8,-6,3)
d. =(9,9.2) – t(-8,- 6,3)

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.

idk what the heck he answer is, i’m just putting this here so i finish my account