Mathematics, 16.04.2020 15:41, s913823
8\times 7 = \purpleC(~8Ć7=( 8, times, 7, equals, start color #aa87ff, left parenthesis, end color #aa87ff, space {}\purpleC{ \times 7)}+\greenD{(3 \times 7)}Ć7)+(3Ć7)start color #aa87ff, times, 7, right parenthesis, end color #aa87ff, plus, start color #1fab54, left parenthesis, 3, times, 7, right parenthesis, end color #1fab54 \phantom{8\times 7 }={}8Ć7=empty space, equals {}+\greenD{21}+21plus, start color #1fab54, 21, end color #1fab54 \phantom{8\times 7 }={}8Ć7=empty space, equals
Answers: 2
Mathematics, 21.06.2019 20:40, mimithurmond03
In each of the cases that follow, the magnitude of a vector is given along with the counterclockwise angle it makes with the +x axis. use trigonometry to find the x and y components of the vector. also, sketch each vector approximately to scale to see if your calculated answers seem reasonable. (a) 50.0 n at 60.0Ā°, (b) 75 m/ s at 5Ļ/ 6 rad, (c) 254 lb at 325Ā°, (d) 69 km at 1.1Ļ rad.
Answers: 3
8\times 7 = \purpleC(~8Ć7=( 8, times, 7, equals, start color #aa87ff, left parenthesis, end color #a...
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