Question 11: Please help. What is the equation of the line that is parallel to y−5=−13(x+2) and passes through the point (6,−1)?
The equation will be in slope-intercept form.

Step-by-step explanation:

Assume that you have two distinct and nonvertical lines, ℓ 1 {\ell _1} ℓ1 and ℓ 2 {\ell _2} ℓ2 in Slope-Intercept Form. They are parallel lines if their slopes are equal or the same. They are perpendicular lines if their slopes are opposite reciprocals of each other, or the product of their slopes equals −1.

Answer is y= -1

x is greater than 5

step-by-step explanation:

2x+7 is greater than 17

    -7                           -7

2x is greater than 10

divide by 2 each side

x is greater than 5

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)