Why is the information in the diagram enough to determine that △LMN ~ △PON using a rotation about point N and a dilation?

because both triangles appear to be equilateral
because∠MNL and ∠ONP are congruent angles
because one pair of congruent corresponding angles is sufficient to determine similar triangles
because both triangles appear to be isosceles, ∠MLN ≅ ∠LMN, and ∠NOP ≅ ∠OPN

mnkjn

step-by-step explanation:

tell you what. i'll find the length of the medians and you can fill in the blanks where they belong.

br

b = (2a,0)

r = (a/2,b/2) remember these things are medians. they go to the 1/2 way point of the line opposite the vertex they face.

br^2 =   (2a - a/2)^2 + (0 - b/2)^2

br^2 = (3/2 a) ^2 + b^2 / 4

br^2 = 9/4 a^2 + b^2 / 4   we need to find some relationship between a and b.

let's try ab = bc  

ab = 2a

bc = (2a - a)^2 + (b - 0)^2

bc = sqrt(a^2 + b^2)

ab = bc

2a = sqrt(a^2 + b^2) square both sides.

4a^2 = a^2 + b^2 subtract a^2 from both sides.

sqrt(3a^2) = sqrt(b^2)

sqrt(3)a = b

let's put b into br^2

br^2 = 9/4 a^2 + 3b^2 / 4

br^2 = 12 a^2 / 4

br^2 = 3a^2 

br = sqrt(3) * a

cp

c = (a,b) ; p = (a,0) this is another application of the distance formula, and it is a good one.

cp^2 = (a - a)^2 + (b - 0)^2

cp^2 = 0 + b^2

cp^2 = b^2 which you can see from the diagram. 

cp = sqrt(b^2)

cp = b but b = sqrt(3) * a 

cp = sqrt(3)*a

aq

a = (0,0)

q = (3/2) a, b/2

aq^2 = (3a/2 -0)^2 + (b/2 - 0)^2

aq^2 = 9a^2/4 + b^2/4

but b = sqrt(3) * a 

aq^2 = 9a^2 / 4 + (sqrt(3)*a)^2 /4

aq^2 = 9 a^2/ 4 + 3 a^2 / 4

aq^2 = 12 a^2/4

aq^2 = 3 a^2

aq = (sqrt  3) * a which agrees with the other two.

answer: 89 x 5

step-by-step explanation:

the answer is: 5,953.2 mm²

you have the  8-sided octahedron as a composite figure that has 2 square pyramids. so, you should   apply the formula for the calculated area of a square pyramid as so:   a=s²+2sl

  a is the area of the square pyramid.

  s will be the base of the square pyramid (s = 33 mm).

  l is the slant height of the square pyramid (l = 28.6 mm).

then, when you substitute these values into the formula you get:

  a=s²+2sl

  a=(33 mm)²+2(33 mm)(28.6 mm)

  a=1089 mm²+1887.6 mm²

  a=2,976.6 mm²

thus, the area of the  surface area of the octahedron is:

sa = 2a

sa = 2(2,976.6 mm²)

sa = 5,953.2 mm²

thus the answer will be: 5,953.2 mm²