Find the standard form of the circle with general form x2 + y2 - 10x + 6y - 2 =0

i think the answer is .36

step-by-step explanation:

what i did was only 2.88 divided by 8

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answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°