A cone frustum is inscribed in a sphere of radius 13. If one of the bases of the frustum is a great circle of the sphere, and the other base has radius 12, what is:

The height of the frustum?

5

Step-by-step explanation:

According to the question, A cone frustum is inscribed in a sphere of radius 13. If one of the bases of the frustum is a great circle of the sphere, and the other base has radius 12.We are now asked to find the height of the frustum.

---The height of this frustum is equal to the distance of its smaller base from the center of the sphere.

Therefore,it is assigned the pattern

H = √(r1² - r2²

Where r1 is the radius of the sphere

And r2 is the radius of the other base of the frustum

H is the height that we are looking for

H = √(13² - 12²)

= √( 169 - 144 )

= √ 25

H = 5

1. 3.4/4

2. 0.8/7

3. 0.5 x 3

4. 0.9 x 6

5. 10.8

6. 2.35

7. 0.567

8. 9.35

9. 0.02

10. 0.06

11. 0.16

12. 0.42

13. 0.63

14. 5.6

15. 8.1

16. 9.9

17. 0.28

18. 0.48

19. 0.27

20. 0.49

21. 0.45

22. 0.72

23. 0.9

24. 0.88

25. 0.75

26. 0.16

27. 0.328

28. 0.495

29. 0.72

30. 1.068

answer:

125 yards

explanation:

75+50=125. that is my answer