Given a soda ca with a volume of 21 and a diameter of 6, what is the volume of a cone that fits perfectly inside the soda can?

The volume of a cone that fits perfectly inside the soda can is 7.

Volume of a can:

21 = r² π h

21 = 3² π h

21 = 9 π h

h = 21/ 9π = 7/ 3π 

Volume of a cone that fits perfectly inside a can:

V = 1/3 r² π h = 1/3 · 9 π · 7 / 3π = 7

Or you can use: V cone = 1/3 V cylinder ( with the same basis )

V cone = 1/3 * 21 = 7

Step-by-step explanation:

Since we have given that

Volume of soda can = 21

Diameter of can = 6

As we know the formula for "Volume of cylinder:"

Now, we have to find the volume of a cone that fits perfectly inside the soda can.

so, its radius will be 3 cm and height will be

As we know the formula for "Volume of cone":

Hence, the volume of a cone that fits perfectly inside the soda can is 7.

step-by-step explanation:

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180