A group of 52 people attend a ball game there were three times as many children as adults in the group set up a system of equations that represents the number of adults and children who attended the game and solve the system to find the number of children who were in the group.

Therefore there total of 39 children presented in group of people who attended a ball game.

Step-by-step explanation:

Given:

Total people present=52 .

And there are 3 times children as adults

To Find:

No.of Children Present in Group.

Solution:

Consider  'x'  be the children and 'y' be Adults presented in group.

So there are total of 52 people.

Therefore Equation becomes,

x+y=52.

And also there  are 3 times children presented in group as adults were.

So

Children=3 times adults

i.e.x=3y

Using in above Equation we get ,

x+y=52

3y+y=52

4y=52

y=52/4

y=13

Hence there are 13 adults  presented in group

So ,

No.of Children=x=3y

=3(13)

=39

No.of.Children =39

{x = -1/2 ,   y = -1

step-by-step explanation:

solve the following system:

{2 x + y = -2

{10 x - 3 y = -2

in the first equation, look to solve for y:

{2 x + y = -2

{10 x - 3 y = -2

subtract 2 x from both sides:

{y = -2 x - 2

{10 x - 3 y = -2

substitute y = -2 x - 2 into the second equation:

{y = -2 x - 2

{10 x - 3 (-2 x - 2) = -2

10 x - 3 (-2 x - 2) = (6 x + 6) + 10 x = 16 x + 6:

{y = -2 x - 2

{16 x + 6 = -2

in the second equation, look to solve for x:

{y = -2 x - 2

{16 x + 6 = -2

subtract 6 from both sides:

{y = -2 x - 2

{16 x = -8

divide both sides by 16:

{y = -2 x - 2

{x = -1/2

substitute x = -1/2 into the first equation:

{y = -1

{x = -1/2

collect results in alphabetical order:

answer:   {x = -1/2 ,   y = -1