Suppose that the price p (in dollars) and the weekly sales x (in thousands of units) of a certain commodity satisfy the demand equation 8p cubedplusx squaredequals104 comma 000. Determine the rate at which sales are changing at a time when xequals200, pequals20, and the price is falling at the rate of $.50 per week.

dx/dt = 12 (in thousands of units /week)

Step-by-step explanation:

We have from problem statement that:

8*p³ + x² = 104    (1)

Where p is price in $, and "x" is the weekly sales in thousands of units

All variables  x  and  p change in relation to time then

Differentiating on both sides of the equation, we get:

24*p²*dp/dt +  2*x*dx/dt = 0      (1)

We need to find dx/dt and we know

p = 20

x = 200

And price is falling at the rate of 0,5 $/week

Then plugging these values in equation (1)

24*p²*dp/dt  = - 2*x*dx/dt

24*(20)²(-0,5) = -400*dx/dt

-4800  = -400*dx/dt

dx/dt = 4800/400

dx/dt = 12 (in thousands of units /week)

2 liters for 10   people

step-by-step explanation:

measurement of the swimming pool is given as = 7 yards 4.79 feet

first we will convert this to yards only.

1 foot = 0.33 yards

so, 4.79 feet = yards

so total yards are = yards

now we will convert this in meters.

1 yard = 0.914 meters

8.580 yards = meters

0.842 m = 0.842*100 = 84.2 cm

this becomes 7 meters and 84.2 cm

hence, the pool is 7 meters and 84.2 cm wide.