Let Z be a standard normal random variable and calculate the following probabilities, drawing pictures wherever appropriate. (Round your answers to four decimal places.) (a) P(0 ≤ Z ≤ 2.87) .9979 Incorrect: Your answer is incorrect. (b) P(0 ≤ Z ≤ 2) .9772 Incorrect: Your answer is incorrect. (c) P(−2.20 ≤ Z ≤ 0) .0139 Incorrect: Your answer is incorrect. (d) P(−2.20 ≤ Z ≤ 2.20) .9633 Incorrect: Your answer is incorrect. (e) P(Z ≤ 1.01) .8438 Correct: Your answer is correct. (f) P(−1.95 ≤ Z) .0256 Incorrect: Your answer is incorrect. (g) P(−1.20 ≤ Z ≤ 2.00) .8621 Correct: Your answer is correct. (h) P(1.01 ≤ Z ≤ 2.50) 0.15 Correct: Your answer is correct. (i) P(1.20 ≤ Z) .8849 Incorrect: Your answer is incorrect. (j) P(|Z| ≤ 2.50) .9938 Incorrect: Your answer is incorrect.

a) 0.49795

b) 0.47725

c) 0.4861

d) 0.9722

e) 0.84375

f) 0.02559

g) 0.86218

h) 0.15004

i) 0.11507

j) 0.9876

Step-by-step explanation:

attached is the statistical table for your reference.

(a) P(0 ≤ Z ≤ 2.87)

    P( Z ≤ 2.87) - P(Z ≤ 0)       ⇒From statistical table of positive z values

    = 0.99795 - 0.5 = 0.49795

(b) P(0 ≤ Z ≤ 2)

    P( Z ≤ 2) - P(Z ≤ 0)       ⇒From statistical table of positive z values

    = 0.97725 - 0.5 = 0.47725

(c) P(−2.20 ≤ Z ≤ 0)

    P( Z ≤ 0) - P(Z ≤ -2.20)       ⇒From statistical table of positive&negative z values

    = 0.5 - 0.01390 = 0.4861

(d) P(−2.20 ≤ Z ≤ 2.20)

    P( Z ≤ 2.20) - P(Z ≤ -2.20)       ⇒From statistical table of positive&negative z values

    = 0.98610 - 0.01390 = 0.9722

(e) P(Z ≤ 1.01)       ⇒From statistical table of positive z values

    0.84375

(f) P(−1.95 ≤ Z)

   P(Z ≥ −1.95)

   = 1 - P(Z < 1.95)       ⇒From statistical table of positive z values

   = 1 - 0.97441 = 0.02559

(g) P(−1.20 ≤ Z ≤ 2.00)

    P( Z ≤ 2.00) - P(Z ≤ -1.20)       ⇒From statistical table of positive&negative z values

    = 0.97725 - 0.11507 = 0.86218

(h) P(1.01 ≤ Z ≤ 2.50)

    P( Z ≤ 2.50) - P(Z ≤ 1.01)       ⇒From statistical table of positive z values

    = 0.99379 - 0.84375 = 0.15004

(i) P(1.20 ≤ Z)

   P(Z ≥ 1.20)

   = 1 - P(Z < 1.20)       ⇒From statistical table of positive z values

   = 1 - 0.88493 = 0.11507

(j) P(|Z| ≤ 2.50)

   P(-2.50 ≤ Z ≤ 2.50)

   P(Z ≤ 2.50) - P(Z ≤ -2.50)      ⇒From statistical table of positive&negative z values

   = 0.9938 - 0.0062

   = 0.9876

55 because 55 + 55 = 110 good luck babe